Neco Gce 2016 Physics Practical Answers – Nov/Dec Expo

(1a)
PLS DRAW A TABLE:
i|Mi(cm)|Mi(g)|Li(cm)(Raw)|Li(cm)(Real)|e=li-lo:
1|4.75 |47.50 |2.60|5.20 |1.40|
2|6.13 |61.30 |3.15|6.30 |2.50|
3|8.53 |85.80 |3.72|7.40 |3.60|
4|10.43|104.30|4.30|8.60 |4.80|
5|12.28|122.80|4.85|9.70 |5.90|
6|14.20|142.00|5.40|10.80|7.00|
Slope= De(cm)/DM(g) = e2-e1/M2-M1

1 aii )

State Ohms Law .

Ohm ' s law states that the current through a

conductor between two points is directly

proportional to the potential difference across

the two points.

( 1 aix )

- i avoided error due to parallax

- i ensure that the mass is gently dropped into

the liquid

( 1 aviii )

Slope = ( 250 . 0 -150 . 0 ) / ( 647 . 10 -323 . 55 )

= 100 . 0 / 323 . 55

= 0 . 309

1 b) archimedes principle states that when a

body is immersed completely or partially in a

liquid ( water ) it experience an upthrust which

is equal to the weight of d liquid displaced by

it

.

( 1 bi)

mass of 7 . 5 cm^ ( 3 )

14 . 2 g

.

( 1 bii )

vol of the wood = 2 . 0 *10 ^ -5 m ³

mass = 5 . 0 * 10 ^ - ³

g = 10 . 0 ms ^ - ²

Density of water = 1 . 0 * 10³ kgm ^ -³

Vol of object = mass / density

Density = mass / volume

Density of the object = mass of the object /

volume

5 . 0 *10 ^ -³ / 2 . 0 * 10 ^ - 5

= 2 . 5 *10² kgm ³

Upthrust = vol of object density of liquid g

2 . 0 *10 ^ -5 * 1 . 5 * 10² * 10

= 0 . 3 N

============

3 )

TABULATE READINGS

R ( N ) - | 2 . 00 | | 4 . 00 | | 6 . 00 | | 8 . 00 | | 10 .

00 |

1 ( A ) - | 2 . 85 | | 2 . 21 | | 2 . 00 | | 1 . 75 | | 1 .

65 |

R ^ - 1 - | 1 . 05 | | 0 . 25 | | 0 . 17 | | 0 . 13 | | 0 .

10 |

( 3 a ) PRECAUTIONS

i ) i ensured clean terminals

ii ) i avioved zero error on the ammeter used

iii ) i ensured tight connection of all wires

3 b )

ohm ' s law states that the current flowing

through a metallic conductor is proportional

to

its portential difference provided that

physical

condition is constant i . e V x I

.

( 3 bii )

E & L

E = kL

E / L = k

E 1 / L 1 = E 2 / L 2

l 2 = E 2 L 1 / E 1 = ( 1 . 5 *1 ) / 2 . 5

L 2 = 0 . 6 cm

the new balance point when 1 . 5 v cell is

connected across it is 0 . 6 cm

.

3 c )

slope ( s ) = DR ^ - 1 / DI = 0 . 25 -0 . 10 / 2 . 21 - 1 . 65

= 0 . 15 / 0 . 56

slope ( s )= 0 . 27

intercept c = - 0 . 35

evaluation

1 / 5 = 1 / 0 . 27 = 3 . 70

evalution

1 / C = 1 / -0 . 35

= - 2 . 86

>

==============COMPLETED===========